[HOT] Downloadgamelogikamenyeberangjembatan

Download Game Logika Menyeberang Jembatan: A Challenging Puzzle Game for Your Brain

If you are looking for a game that can test your logic and problem-solving skills, you might want to try Download Game Logika Menyeberang Jembatan. This is a puzzle game that involves a family of five people who need to cross a bridge at night with only one flashlight that can last for 30 seconds. The bridge can only hold two people at a time, and each person has a different speed of crossing: 1 second, 3 seconds, 6 seconds, 8 seconds, and 12 seconds. The challenge is to find a way for the whole family to cross the bridge safely within the time limit.

This game is based on a popular logic puzzle that has been featured in various sources, such as YouTube[^1^], websites[^2^] [^3^], and blogs[^4^]. The game is designed to stimulate your brain and improve your reasoning abilities. You will need to think carefully and creatively to find the optimal solution. There may be more than one possible answer, but some may be more efficient than others.

Download Game Logika Menyeberang Jembatan is a fun and educational game that can challenge your mind and entertain you at the same time. You can download it from the link below and enjoy playing it on your computer or mobile device. Can you solve the puzzle and help the family cross the bridge

Download Game Logika Menyeberang JembatanHow to Solve the Puzzle

The puzzle is also known as the bridge and torch problem, and it belongs to the category of river crossing puzzles. The goal is to find the minimum time required for all people to cross the bridge with the given constraints. There are different variations of the puzzle, but the most common one involves four people with crossing times of 1, 2, 5, and 8 minutes respectively.

One possible way to solve the puzzle is to use a trial and error method, where you try different combinations of people crossing the bridge and see which one gives the lowest total time. However, this can be tedious and inefficient, especially if there are more people or different crossing times involved. A better way is to use some logic and observation to find a general strategy that can be applied to any case.

One key observation is that when two people cross the bridge together, they must move at the slower person's pace. This means that the faster person's time is not counted in the total time. Therefore, it makes sense to pair up the slowest people together, so that their time is not wasted. Another observation is that when someone returns with the torch, they should be the fastest person available, so that they minimize the time spent on going back.

Based on these observations, we can devise a general strategy for solving the puzzle:[^2^] [^3^]

Let A be the fastest person, B be the second fastest person, C be the third fastest person, and D be the slowest person.

A and B cross the bridge together. A returns with the torch.

C and D cross the bridge together. B returns with the torch.

A and B cross the bridge together again.

This strategy ensures that the slowest people (C and D) cross only once, and that the fastest person (A) returns twice. The total time for this strategy is:

(A + B) + A + (C + D) + B = 2A + 2B + C + D

For example, if A = 1 minute, B = 2 minutes, C = 5 minutes, and D = 8 minutes, then the total time is:

(1 + 2) + 1 + (5 + 8) + 2 = 19 minutes

This strategy works for any case where A < B < C < D. However, there may be some cases where this strategy is not optimal. For example, if A = 1 minute, B = 2 minutes, C = 3 minutes, and D = 10 minutes, then the total time is:

(1 + 2) + 1 + (3 + 10) + 2 = 19 minutes

But there is a better solution that takes only 17 minutes:

A and C cross the bridge together. A returns with the torch.

A and D cross the bridge together. C returns with the torch.

A and B cross the bridge together again.

The total time for this solution is:

(A + C) + A + (A + D) + C = 3A + 2C + D

If A = 1 minute, B = 2 minutes, C = 3 minutes, and D = 10 minutes, then the total time is:

(1 + 3) + 1 + (1 + 10) + 3 = 17 minutes

This solution works for any case where A < B < C < D and C < A + B. In general, we can say that if C < A + B, then we should pair up A with C and A with D; otherwise, we should pair up A with B and C with D. 248dff8e21